TS EAMCET 4 May 2018 Shift 2 Solved Paper

Consider the given equation,
8x+3√2y=36
And,

x2

9

+

y2

4

=2

xx1

9

+

yy1

4

−2=0 ........(I)
And,
8x+3√2y−36=0 ......(II)
Since equation (I) and (II) represents same line so,

x1

9(8)

=

y1

4(3√2)

=

1

18

From above,
x1=4=a
And,
y1=

12√2

18

=b
This implies,
a+√2b=4+√2

2√2

3

12+43=

16

3