If y=\tan ^{-1}(\sin \sqrt{x})+ {\cosec}^{-1} (e^{2 x+1} ) then \frac{d y}{d x}=

Correct Answer is : cos√x2√x(1+sin2√x)−2√e4x+2−1

{1}/{2 \\sqrt{x} (1+\sin ^{2} \sqrt{x} )}+ {2}/\sqrt{e^{4 x+2}+1}}

{\cos \sqrt{x}/{2\sqrt{x} (1+\sin ^{2} \sqrt {x} )}- {2}/\sqrt{e^{4 x+2}-1}}

{\cos \sqrt{x}/{ (1+\sin ^{2} \sqrt{x} )}+ {2}/\sqrt{e^{4 x+2}+1}}

{1}/{2\sqrt{x} {\cos\sqrt{x}/{ (1+\sin ^{2} \sqrt{x} )}- {2}/\sqrt{e^{2 x+2}-1}}

TS EAMCET 4 May 2018 Shift 2 Solved Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

If y=tan−1(sin‌√x)+cosec−1(e2x+1) then

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