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Question : 75 of 160
Marks:
+1,
-0
Solution:
Consider the expression,
‌ =‌ Let,
x= then
dx=. the limit value will be from 0 to
1. So,
4‌dx Let
1+x4=t then
4x3dx=dt Then,
=[ln‌t]12 =ln‌2−ln‌1 ln‌2=p ep=eln‌2 ep=2
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