TS EAMCET 4 May 2018 Shift 2 Solved Paper

Consider the following figure.
The total force in x-direction is calculated as follows,
∑Fx=15‌cos‌60°+19−11‌cos‌30° −16‌cos‌45°
=5.66N
The total force in y-direction is calculated as follows,
∑Fy=−22+15‌sin‌60°+16‌cos‌45° −11‌sin‌30°
=−3.196N
The resultant force is calculated as follows,
R=√Fx2+Fy2
=√(5.66)2+(−3.196)2
=6.5N
Direction of resultant,
tan‌θ=

Fy

Fx

=

−3.196

5.66

=330°