TS EAMCET 7 May 2018 Shift 1 Solved Paper

The image of point A(2,4) is C(a,b). The line AB is perpendicular to the mirror.
The coordinate of the mid-point of line AC is (

a+2

2

,

b+4

2

)
This point will satisfy the line 2x+3y−6=0 .
2(

a+2

2

)+3(

b+4

2

)−6=0
2a+3b+4=0
since the mirror and line is perpendicular. The product of theslope will be equal to (-1)

a−4

b−2

×−

2

3

=(−1)
3a−2b+2=0
Solve the two equations a=

−14

13

,b=

−8

13

The image of point is (

−14

13

,

−8

13

)