∫ \frac{cos2x.sin4x}{\cos^4x(1+\cos^22x)} dx =

Correct Answer is : log ((1+cos2x)21+cos22x)+sec2 x + c

log [\frac{1+\cos^2 2x}{1+cos2x}] - \tan^2 x + c

log (\frac{1+\cos^2 2x}{1+cos2x}) + \tan^2 x + c

log (\frac{1+\cos 2x}{1+\cos^2 2x}) + \sec^2 x + c

log ((1+\cos 2x)^2/{1+\cos^2 2x}) + \sec^2 x + c

TS EAMCET 7 May 2018 Shift 1 Solved Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫

cos2x.sin4x

cos4x(1+cos22x)

dx =

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