In a nuclear reactor of efficiency 25 \%, the number of fissions taking place per second is 5 \times 10^{13}. If 200 MeV energy is released per fission, then the output power of the reactor is [TG EAPCET 7 May 2024 Shift 1]

TS EAMCET 7 May 2024 Shift 1 Solved Paper

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In a nuclear reactor of efficiency 25%, the number of fissions taking place per second is 5×1013. If 200 MeV energy is released per fission, then the output power of the reactor is

[TG EAPCET 7 May 2024 Shift 1]

6400 W
1600 W
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400 W

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