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Question : 58 of 160
Marks:
+1,
-0
Solution:
AB=√(4−3)2+(1−2)2+(0+1)2
=√1+1+1=√3AC‌=√(2−3)2+(1−2)2+(4+1)2‌=√1+1+25‌=√27=3√3By angle bisector theorem,
‌=‌=‌=‌=1:3The point
D divides the segment
BC internally in the ratio
1:3∴ Coordinate of
D will be
(‌,‌,‌)i.e.
(‌,1,1)Given,
D≡(p,q,r)∴‌‌p=‌,q=1‌ and ‌r=1Now,
√2p+q+r=√2(‌)+1+1=√9=3
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