The value of b^2 in order that the foci of the hyperbola x^2/144-y^2/81=1/25 and the ellipse x^2/16+y^2/b^2=1 coincide is

TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

Section: Mathematics

Question : 57 of 160

Marks: +1, -0

The value of b2 in order that the foci of the hyperbola

144

−

and the ellipse

=1 coincide is

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