TS EAMCET 9-Sep-2020 Shift 1 Solved Paper

According to given situation,As there is no external force, velocity and hence KE of centre of mass remains same before and after collision.
Now, Kinetic energy of centre of mass is given ‌

4

3

J.
∴‌‌‌

4

3

=‌

1

2

(M+1)⋅vCM2
⇒‌‌8(M+1)=3(2M+1)2
⇒‌‌12M2+4M−5=0
⇒‌‌12M2+10M−6M−5=0
⇒2M(6M+5)−1(6M+5)=0
⇒‌‌(2M−1)(6M+5)=0
⇒‌‌M=‌

1

2

or M=‌

−5

6

So, mass, M=‌

1

2

=0.5kg