TS EAMCET Engineering 12 May 2023 Shift 1 Solved Paper

Section: Mathematics

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Question : 52 of 160

Marks: +1, -0

The equation of the parabola with x+2y=1 as directrix and (1,0) as focus is

[TG EAPCET 12 May 2023 Shift 1]

4x2−4xy+y2−8x+4y+4=0
4x2−4xy+y2−4x+4y+4=0
4x2−4xy+y2+8x+4y+4=0
x2−4xy+y2−8x+4y+4=0

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