\int \frac{d x}{ (x^2+1) (x^2+4) }= [TG EAPCET 14 May 2023 Shift 1]

Correct Answer is : 13Tan−1x−16Tan−1(x2)+c

\frac{1}{3} {\Tan}^{-1} x+\frac{1}{6} {\Tan}^{-1} (\frac{x}{2}) + {\c}

\frac{1}{3} {\Tan}^{-1} x-\frac{1}{3} {\Tan}^{-1} (\frac{x}{2}) + {\c}

\frac{1}{3} {\Tan}^{-1} x+\frac{1}{3} {\Tan}^{-1} (\frac{x}{2}) + {\c}

\frac{1}{3} {\Tan}^{-1} x-\frac{1}{6} {\Tan}^{-1} (\frac{x}{2}) + {\c}

TS EAMCET Engineering 14 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫‌

(x2+1)(x2+4)

[TG EAPCET 14 May 2023 Shift 1]

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