TS EAMCET Engineering 14 May 2023 Shift 1 Solved Paper

Section: Mathematics

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Question : 80 of 160

Marks: +1, -0

The general solution of the differential equation (x2+2)dy+2xy‌dx=ex(x2+2)‌dx is

[TG EAPCET 14 May 2023 Shift 1]

‌
x
y
=ex(x2+x−4)+c
2xy=ex(x2−2x+4)+c
(x2+2)y=ex(x2−2x+4)+c
(x2+2)2y=ex(x2+2x−4)+c

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