An aqueous solution of a non-volatile solute boils at 100.17^{\circ} {\C}. The temperature at which this solution will freeze (in { }^{\circ} {\C} ) is ( {\K}_{ {\b}} ( {\H}_2 {\O}) =0.512{ }^{\circ} {\C} {\kg} {\mol}{ }^{-1}, {\K}_{ {\f}} ( {\H}_2 {\O}) =1.86^{\circ} {\Ckg} {\mol}^{-1}) [TG EAPCET 14 May 2023 Shift 2]

TS EAMCET Engineering 14 May 2023 Shift 2 Solved Paper

Section: Chemistry

Question : 140 of 160

Marks: +1, -0

An aqueous solution of a non-volatile solute boils at 100.17∘C. The temperature at which this solution will freeze (in ‌∘C ) is
(Kb(H2O)=0.512‌∘C‌kg‌mol‌‌−1,Kf(H2O)=1.86∘‌Ckg‌mol−1)

[TG EAPCET 14 May 2023 Shift 2]

−0.62
−0.512
−1.24
−1.86

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