TS EAMCET Medical 30 Jul 2022 Shift 2 Paper
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Question : 85 of 160
Marks:
+1,
-0
The position of a particle is
= x
+ y
where x and y are function of time t and given as x = ( 12 + 5 t − t 2 ) m and y = ( 18 − 5 t + t 2 ) m . At t = 1 s , the magnitude of the velocity vector of the particle is
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