\tan ^{2} {\\pi}{3}+\cot ^{2} \frac{\\pi}{4}-\sec ^{2} \frac{\\pi}{3}+8 \cos ^{2} \frac{\\pi}{6}=

TS ICET 1 Oct 2020 Shift 1 Paper

Question : 119 of 200

Marks: +1, -0

\tan ^{2} {\π}{3}+\cot ^{2} {\π}/{4}-\sec ^{2} {\π}/{3}+8 \cos ^{2} {\π}/{6}=

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