TS ICET 2017 Question Paper with Solutions for online practice

Question : 136 of 200

Marks: +1, -0

In ΔABC the bisectors of ∠B and ∠C meet at D. Then ∠BDC =

Solution:

∠A + ∠B + ∠C = 180°

∠D+1/2∠B+1/2∠C=180°

⇒ 2∠D + ∠B + ∠C = 360°
⇒ 2∠D + (180°– ∠A) = 360°
⇒ 2∠D = 180°+ ∠A

∴∠D=90°+1/2∠A

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