TS ICET 2017 Question Paper with Solutions for online practice

Note : In a code the ${10}^{\mathrm{th}}$ letter J of the English alphabet is coded as Z and for any k ≠ 10, the ${\mathit{k}}^{\mathrm{th}}$ letter is coded as ${\mathit{r}}^{\mathrm{th}}$ letter where r is the remainder when k + 2 is divided by 26. (For example, the $7^{\mathrm{th}}$ letter G is coded as ${11}^{\mathrm{th}}$ letter K since 5 × 7 + 2 = 37 leaves remainder 11 when divided by 26). The reverse process is used for decoding. Using these processes of coding and decoding answer Q. Nos. 56 to 60.