TS ICET 23 May 2018 Shift 2 Paper

Question : 137 of 200

Marks: +1, -0

If the angles of a quadrilateral are in the ratio 3:4:5:6 then the smallest of these angles is

Solution:

Let the angles be 3K, 4K, 5K, 6K

⇒ 3K + 4K + 5K + 6K = 360°

18K = 360°⇒K = 20°

Smallest angle is 3K = 60°

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