TS ICET 23 May 2018 Shift 2 Paper

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Question : 77 of 200

Marks: +1, -0

2^{\x^2-4}= 1/{16^(10-3\x)}

⇒ x =

6
4
-6
-2

Solution:

Given

2^{x^{2}-4}=\;{1}/{16^{10-3 x}}=2^{-4(10-3 x)}

⇒ x^{2}-4=-40+12 x

⇒ x^{2}-12 x+36=0

⇒(x-6)^{2}=0

⇒ x=6

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