TS ICET 23 May 2018 Shift 2 Paper

Question : 85 of 200

Marks: +1, -0

What is smallest number of 5 digits which is divisible by 12, 15, 20 and 35?

Solution:

The smallest number divisible by 12, 15, 20 and 35 is LCM

(12, 15, 20, 35) = 420

10000/420 ≈ 23.8

The smallest five-digit number that is divisible by 420 is

420×24 = 10080

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