TS ICET 23 May 2019 Shift 1 Paper

Question : 130 of 200

Marks: +1, -0

The term independent of .r in the expression of

(2x^2+1/x^2)^8

Solution:

let

T_{r+1}

be the independent term,

r={np}/{p+q}

={8×2}/{2+2}=4

∴ Independent term = 5th term.

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