TS ICET 23 May 2019 Shift 2 Paper

Question : 110 of 200

Marks: +1, -0

The sum

(1010)_(2)+(102)_(3)

Solution:

(1010)_{2}+(102)_{3}

=2^{3}+0+2+3^{2}+0+2

=(21)_{10}=(10101)_{2}

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