TS ICET 23 May 2019 Shift 2 Paper

Question : 126 of 200

Marks: +1, -0

If a number x exceeds its reciprocal by

2 2/3

, than

x^2

Solution:

Given

x-1/x=2{2/3}

x^2-1={8x}/3

3 x^{2}-8 x-3=0

(3 x+1)(x-3)=0

⇒ x=3 ⇒ x^{2}=9

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