TS ICET 23 May 2019 Shift 2 Paper

Question : 144 of 200

Marks: +1, -0

The standard deviation of first 25 natural numbers

Solution:

S.D of the first 25 natural numbers is

=√{\;{n^{2}-1}/{12}}

here

n=25

=√{\;{624}/{12}}=√{52}

=2 √{13}

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