1/{\sqrt5-2}-1/{2-\sqrt3} + 1/{\sqrt3-\sqrt2}-1/{\sqrt2-1} +1 =

TS ICET 23 May 2019 Shift 2 Paper

Question : 80 of 200

Marks: +1, -0

1/{√5-2}-1/{2-√3}

1/{√3-√2}-1/{√2-1} +1

Solution:

{1}/{√{5}-2}-\;{1}/{2-√{3}}+\;{1}/{√{3}-√{2}}-\;{1}/{√{2}-1}+1

√{5}+2-(2+√{3})+√{3}+√{2}-(√{2}+1)+1

√{5}+2-(2+√{3})+√{3}+√{2}-√{2}-1+1

=√{5}

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