The value of the determinant |\table1-\alpha,\alpha-\alpha^2,\alpha^2;1-\beta,\beta-\beta^2,\beta^2;1-\gamma,\gamma-\gamma^2,\gamma^2| is equal to [NDA II 2017]

Correct Answer is : (α−β)(β−γ)(γ−α)

(\alpha-\beta)(\beta-\gamma)(\alpha-\gamma)

(\alpha-\beta)(\beta-\gamma)(\gamma-\alpha)

(\alpha-\beta)(\beta-\gamma)(\gamma-\alpha)(\alpha+\beta+\gamma)

UPSC NDA 2 2017 Mathematics Solved Paper

Question : 96 of 120

Marks: +1, -0

The value of the determinant |

| is equal to

[NDA II 2017]

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