UPSC NDA II 2015 Mathematics Solved Paper

Equation of circle having radius r and centre (3,4) is
=(x−3)2+(y−4)2=r2
if it is passing through (0, 0)
∴(0−3)2+(0−4)2=r2
⇒r2=25
equation of circle is
(x−3)2+(y−4)2=25
putting y=0
∴x=6 unit = interception x-axis intercept on y axis (putting x=0) is y=8 units