UPSC NDA Math Model Paper 4

Here, there are six teams,
So, total way to finish the race = 6!
= 6 × 5 × 4 × 3 × 2 × 1
= 720
Now, A, B, and C are fixed at first, second, third positions
So, the number of ways to place the remaining three D, E, and F will be 3!
= 3 × 2 × 1
= 6
So, probability of getting A, B, C finish first, second, third respectively
= 6/720
= 1/120
Hence, option (4) is correct