If \overrightarrow{a}=\stackrel{\^}{i}+2 \stackrel{\^}{j}-3 \stackrel{\^}{k} and \overrightarrow{b}=2 \stackrel{\^}{i}+3 \stackrel{\^}{j}+\stackrel{\^}{k} then find a unit vector in the direction of \overrightarrow{a}+\overrightarrow{b} ?

Correct Answer is : 3√38^i+5√38^j−2√38^k

{3}/{\\sqrt{38} \stackrel{\^}{i}-{5}/{\\sqrt{38} \stackrel{\^}{j}-{2}/{\\sqrt{38} \stackrel{\^}{k}

{3}/{\\sqrt{38} \stackrel{\^}{i}+{5}/{\\sqrt{38} \stackrel{\^}{j}+{2}/{\\sqrt{38} \stackrel{\^}{k}

{3}/{\\sqrt{38} \stackrel{\^}{i}+{5}/{\\sqrt{38} \stackrel{\^}{j}-{2}/{\\sqrt{38} \stackrel{\^}{k}

UPSC NDA Math Model Paper 5

Question : 103 of 120

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