UPSC NDA Math Model Paper 5

Given: The end points of the diameter of a circle are A (5, - 3) and B (2, - 4).
As we know that, if (x1,y1) and (x2,y2) are the end points of the diameter of a circle then the equation of such a circle is (x−x1).(x−x2)+(y−y1)(y−y2)=0
Here, x1=5,y1=−3,x2=2 and y2=−4
⇒(x−5).(x−2)+(y+3).(y+4)=0
⇒x2+y2−7x+7y+22=0
So, the equation of the required circle is: x2+y2−7x+7y+22=0
Hence, option B is the correct answer.