Xavier Aptitude Test 2013 Paper

Question : 69 of 121

Marks: +1, -0

In a square PQRS, A and B are two points on PS and SR such that PA = 2AS, and RB = 2BS. If PQ = 6, the area of the triangle ABQ is (is it a repeat)

Solution:

(c)

Given, PS = 6
∴ PA + AS = 6
2AS + AS = 6
(∴PA = 2AS)
or, AS = 2
Area of ΔABS =

1/2

× 2 × 2 = 2
Area of ΔAPQ =

1/2

× 6 × 4 = 12
Area of ΔQRB =

1/2

× 4 × 6 = 12
Area of

□

PQRS = 6 × 6 = 36
∴ Area of ΔABQ = Area of

□

PQRS – [Area of ΔABS
+ Area of ΔAPQ + Area of ΔQRB]
= 36 – (2 + 12 + 12) = 10

Go to Question:

Prev Question

Next Question