Xavier Aptitude Test 2022 Paper

Using condition W :
The magnitudes of the net change in enrollment between 2014 and 2021 is closest among any two universities for TRU and MPU.
Going by the color of the lines the net change for different universities is:
$\mathrm{Unit}1:0.7$
$\mathrm{Unit}2:4.4$
$\mathrm{Unit}3:0.1$
$\mathrm{Unit}4:0.2$
$\mathrm{Unit}5:3.3$
The closest among these are: Univ 3 and Univ 4. They can possibly be : $\left(\frac{\mathrm{TRU}}{\mathrm{MPU}}\right)$
Using condition X :
The university LTU must have the same enrollment in consecutive years at least twice :
LTU can either be Unit 3 or Unit 1 but since Unit 3 must be among TRU and MPU. LTU is university 1.

Using condition Y :
The increase in the enrollment of JSU between the years 2015 and 2019 is 50 percent of TRU's total enrollment in 2020.
Considering :
$\mathrm{TRU}=\mathrm{Unit}4$
The enrollment is $5$
$\mathrm{TRU}=\mathrm{Unit}3$
The enrollment is $0.7$
For TRU as Unit 3, there is no university whose increase in enrollment between 2015 and 2019 is $50\%$ of TRU.
Hence $\mathrm{TRU}=\mathrm{Unit}4$
Since the increase in enrollment for JSU is half of TRU. The increase must be half of $5=2.5$
The only possible case is $\mathrm{JSU}=\mathrm{Unit}2$
$\mathrm{MPU}=\mathrm{Unit}3$
$\mathrm{LTU}=\mathrm{Unit}1$
$\mathrm{PKU}=\mathrm{Unit}5$
SInce LTU is unit 1 the university with an enrollment twice that of $\mathrm{LTU}=2\times \left(3.2\right)$
$=6.4$
Hence the only possible case close by is Unit 5 (\PKU)