Xavier Aptitude Test 2022 Paper

The two given sequences in $\mathrm{A}\mathrm{P}$ are :
$\mathit{x},{\mathit{a}}_1,{\mathit{a}}_2,\mathit{y}$ and $\mathit{x},{\mathit{b}}_1,{\mathit{b}}_2,\mathit{z}$
Additionally, it is given that :
$\mathit{y}>\mathit{x}$ and
Hence the common difference is not zero for both the series :
Since $\mathit{y}>\mathit{x}$ the common difference is positive for the first series.(Considering the common difference to be ${\mathit{d}}_1$)
Similarly the common difference is negative for the given series. (Considering the common difference to be ${\mathit{d}}_2$)
Now for the given value :
$\frac{{\mathit{a}}_1-{\mathit{a}}^2}{{\mathit{b}}_1-{\mathit{b}}_2}$
The value of ${\mathit{a}}_1-{\mathit{a}}_2$ is less than zero which is equal to the negative common difference of the series $\left(-{\mathit{d}}_1\right)$
The value of ${\mathit{b}}_1-{\mathit{b}}_2$ is the negative common difference that is equal to the negative common difference of the series $\left(-{\mathit{d}}_2\right)$.
Hence the value of $\frac{{\mathit{a}}_1-{\mathit{a}}_2}{{\mathit{b}}_1-{\mathit{b}}_2}$ is a negative value :
The only possible option is $-1$.