The value of \int {10^{x \/ 2}}/\sqrt{10^{-x}-10^x}} \dx is

Correct Answer is : 1loge10sin−1(10x)+c

\frac{1}{\log _e 10} \sin ^{-1} (10^x) +c

\frac{1}{\log _e 10} \sinh { }^{-1} (10^x) +c

\frac{-1}{\log _e 10} \sinh { }^{-1} (10^x) +c

COMEDK Exam 2018 Solved Paper

Question : 170 of 180

Marks: +1, -0

The value of ∫‌

10x∕2

√10−x−10x

‌dx is

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