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Question : 171 of 180
Marks:
+1,
-0
Solution:
We have,
‌∫ex{‌}‌dx‌=∫ex{‌+‌}‌dx‌=∫ex( sec2+tan‌x)‌dx=∫ex{f′(x)+f(x)}‌dx‌[‌ where ‌f(x)=tan‌x‌ and ‌f′(x)= sec2x]‌=exf(x)+c=ex‌tan‌x+c
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