JEE Main 26 Feb 2021 Shift 2 Solved Paper

Section: Mathematics

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Question : 64 of 89

Marks: +1, -0

For x>0, if f(x)=

x

∫

1

‌

loget

(1+t)

dt, then f(e)+f(‌

1

e

) is equal to

[26 Feb 2021 Shift 2]

1
−1
‌
1
2
0

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