A natural number has prime factorisation given by n=2^{x} 3^{y} 5^{z}, where y and z are such that y+z=5 and y^{-1}+z^{-1}=\frac{5}{6}, y > z. Then, the number of odd divisors of n, including 1 , is [26 Feb 2021 Shift 2]

JEE Main 26 Feb 2021 Shift 2 Solved Paper

Section: Mathematics

Question : 65 of 89

Marks: +1, -0

A natural number has prime factorisation given by n=2x3y5z, where y and z are such that y+z=5 and y−1+z−1=‌

,y>z. Then, the number of odd divisors of n, including 1 , is

[26 Feb 2021 Shift 2]

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