KVPY SA Exam 2014 Question Paper

Question : 71 of 80

Marks: +1, -0

CHEMISTRY

10 moles of a mixture of hydrogen and oxygen gases at a pressure of 1 atm at constant volume and temperature, react to form 3.6 g of liquid water. The pressure of the resulting mixture will be closest to

1.07 atm
0.97 atm
1.02 atm
0.92 atm

Validate

Solution:

\table ,2H_2 ,+, O_2, ––––– ▸, 2H_2O; \Initially, x \mol, ,(10 - x) \mol,,0;\After \reaction ,x-a,, (10-x-a/2),,a

As per problem ;

a=3.6/18=0.2

∴ Resulting mole of gases in the mixture

= x - 0.2 + 10 - x -0.2/2

=10-0.3=9.7

∴ from relation

P_1/ n_1 =P_2/n_2

1/10=P_2/9.7

P_2 = 0.97

atm.

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