NIFT UG 2015 Question Paper with solutions

Question : 54 of 150

Marks: +1, -0

A box contains 7 green, 6 black and 4 yellow balls. How many selections are possible so that we have one ball of each colour.

Solution:

Number of ways of selecting one green ball

=^7C_1

Number of ways of selecting one black ball

=^6C_1

Number of ways of selecting one yellow ball

=^4C_1

Total number of ways

=^7C_1×^6C_1×^4C_1

=7×6×4=168.

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