NIMCET 2008 Question Paper with solutions

Question : 73 of 120

Marks: +1, -0

Larger, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships. 3 medium ships carry the same amount of water as 2 large ships and 1 small ship. 15 large, 7 medium and 14 small ships, each made 36 journeys and brought a certain quantity of water. In how many journeys would 12 large, 14 medium and 21 small ships bring the same quantity of water?

Validate

Solution:

15 large, 7 medium and 14 small ships

=15 × \;{7}/{4}+7 × \;{(2 × {7}/{4}+1)}/{3}+14

small ships

=\;{105}/{4}+\;{21}/{2}+14=\;{203}/{4}

small ships
Now, 12 large, 14 medium and 21 small ships

=12 × \;{7}/{4}+\;{14(2 × {7}/{4}+1)}/{3}+21

sinall ships

=21+21+21=63

small ships
Number of trips by

\;{203}/{4}

ships

=36

So, number of trips by 63 ships

=\;{{203/4 × 36}}/{63}=29

trips.

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