The value of \sin ^{2} 20^\circ+\sin ^{2} 70^\circ-\tan ^{2} 45^\circ +\sec 60^\circ is equal to:

SSC CGL 12 Jun 2019 Shift 2 Paper

Question : 52 of 100

Marks: +1, -0

The value of

\sin ^{2} 20°+\sin ^{2} 70°-\tan ^{2} 45°

+\sec 60°

is equal to:

Solution:

\sin ^{2} 20°+\sin ^{2} 70°-\tan ^{2} 45°

+\sec 60°

\⇒\sin ^{2} 20+\cos ^{2} 20-(1)^{2}+2

\⇒1-1+2=2

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