If \\sqrt{x}- {1}/{\\sqrt{x}=2 \\sqrt{2}, than x^{2}+ {1}/{x^{2}} is equal to:

SSC CGL 12 Jun 2019 Shift 2 Paper

Question : 53 of 100

Marks: +1, -0

\√{x}-\ {1}/{\√{x}}=2 \√{2},

than

x^{2}+\ {1}/{x^{2}}

is equal to:

Solution:

\√{x}-\ {1}/{\√{x}}=2 \√{2}

x+\ {1}/{x}=8+2=10

x^{2}+\ {1}/{x^{2}}=(10)^{2}-2=98

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