If (4a – 3)^2 = 0, then the value of 64a^3 – 48a^2 + 12a + 13 is :

SSC CGL 3 Sep 2016 Paper

Question : 59 of 100

Marks: +1, -0

(4a – 3)^2

= 0, then the value of

64a^3 – 48a^2

+ 12a + 13 is :

Solution:

(4a – 3)^2

= 0 ⇒ 4a – 3 = 0
⇒ 4a = 3 ⇒ a =

3/4

∴

64a^3 – 48a^2

+ 12a + 13
= 64 ×

(3/4)^3

- 48 ×

(3/4)^2

+ 12 ×

3/4

+ 13
= 64 ×

{27}/{64} - {48×9}/{16}

+ 9 + 13
= 27 - 27 + 22 = 22

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