SSC CHSL 12 Oct 2020 Shift 1 Paper

Question : 57 of 100

Marks: +1, -0

\Δ\XYZ, \L

and M are the middle points of the sides XY and XZ, respectively. R is a point on the segment LM, such that

\LR: \RM=1: 2

. If

\LR=3 {\cm}

, then YZ is equal to

Solution:

L, is the mid-point of

\XY, \M

is the mid point of XZ.

{\LR}/{\RM}={1}/{2}

{3}/{\RM}={1}/{2}

(\ ∵\LR=3)

⇒

\RM=6 {\cm}

Now, By mid-point theorem,

\LM={1}/{2} \YZ

(\LR+\RM)={1}/{2} \YZ

(3+6)={1}/{2} \YZ

9={1}/{2} \YZ

\YZ=18 {\cm}

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