SSC CHSL 12 Oct 2020 Shift 1 Paper

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Question : 58 of 100

Marks: +1, -0

The diagonal of rectangle is

15 {\cm}^{2}

and length is

12 {\cm}^{2}

. Find the area of the rectangle.

$114 {\cm}^{2}$
$108{\cm}^{2}$
$116 {\cm}^{2}$
$112 {\cm}^{2}$

Solution:

Length of side

(\CD)=12 {\cm}

,
Diagonal

(\BD)=15 {\cm}

,

Now, in right angled

\Δ\BDC

By Pythagoras theorem,

\BC^{2}=\BD^{2}-\CD^{2}

\BC^{2}=(15)^{2}-(12)^{2}

\BC^{2}=225-144

\BC^{2}=81

\BC=9

∴ Width

=9 {\cm}

Now, Area

=

length

\×

width

=12 \×9=108 {\cm}^{2}

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