SSC CHSL 19 Mar 2020 Shift 3 Paper

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Question : 75 of 100

Marks: +1, -0

In

\Δ\ABC, \AB=\AC

and

\∠\BAC

is

50°

. Then,

\∠\ABC

and

\∠\BCA

are, respectively

$50°$ and $55°$
$65°$ and $65°$
$70°$ and $75°$
$55°$ and $55°$

Solution:

Given,

\∠\BAC=50°, \AB=\AC

∴

\∠\ABC=\∠\BCA=x

(let)
Now, in

\Δ\ABC, \∠\A+\∠\B+\∠\C=180°

[\∵

angle sum property

]

⇒

50°+x+x=180°

⇒

2 x+50°=180°

⇒

2 x=180°-50°=130°

⇒

x={130°}/{2}=65°

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