SSC CHSL 8 Jan 2017 Shift 3 Paper

Question : 61 of 100

Marks: +1, -0

If tanA - cotA = x, then value of x is?

Solution:

Expression : tanA − cotA = x
=

{sinA}/{cosA}-{cosA}/{sinA}

{sin^2A-cos^2A}/ {sinAcosA}

Using,

sin^2A=1-cos^2A

{(1-cos^2A)-cos^2}/ {sinAcosA}

{1-2cos^2A}/{sinAcosA}

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