SSC CHSL 8 Jan 2017 Shift 3 Paper

Equation of line passing thorough points $\left({\mathit{x}}_1,{\mathit{y}}_1\right)$ and $\left({\mathit{x}}_2,{\mathit{y}}_2\right)$ $=\left(\mathit{y}-{\mathit{y}}_1\right)=\frac{\left({\mathit{y}}_2-{\mathit{y}}_1\right)}{\left({\mathit{x}}_2-{\mathit{x}}_2\right)}\left(\mathit{x}-{\mathit{x}}_1\right)$
x-intercept of 4 units implies that the line passes through (4,0)
Points given = (-1,3) and (4,0)
⇒ Equation of line = $\left(\mathit{y}-3\right)=\frac{\left(0-3\right)}{\left(4+1\right)}\left(\mathit{x}+1\right)$
⇒ $\left(\mathit{y}-3\right)=\frac{3}{5}\left(\mathit{x}+1\right)$
⇒ $5\mathit{y}-15=-3\mathit{x}-3$
⇒ $3\mathit{x}+5\mathit{y}=12$