SSC CHSL Model Paper 20

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Question : 73 of 100

Marks: +1, -0

What is the remainder when

x^5 - 5x^2 + 125

is divided by x + 5 ?

0
125
- 3125
3125

Solution:

(x + 5) is the factor of

x^5 - 5x^2 +125

so x = - 5 should be substituted to the equation

x^5 - 5x^2 + 125

to get the remainder
Req. remainder

= (- 5)^5 - 5 (- 5)^2 + 125

= - 3 1 2 5 - 125 + 125 = - 3 1 2 5

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